0=-4.9t^2-200t-150

Solution for 0=-4.9t^2-200t-150 equation:

0=-4.9t^2-200t-150

We move all terms to the left:

0-(-4.9t^2-200t-150)=0

We add all the numbers together, and all the variables

-(-4.9t^2-200t-150)=0

We get rid of parentheses

4.9t^2+200t+150=0

a = 4.9; b = 200; c = +150;
Δ = b2-4ac
Δ = 2002-4·4.9·150
Δ = 37060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{37060}=\sqrt{4*9265}=\sqrt{4}*\sqrt{9265}=2\sqrt{9265}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-2\sqrt{9265}}{2*4.9}=\frac{-200-2\sqrt{9265}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+2\sqrt{9265}}{2*4.9}=\frac{-200+2\sqrt{9265}}{9.8}
$